Try it

Keeps pulsing

Runs automatically: HIGH → LOW → repeat.

HIGHLOWTime

HIGH 762 µs · LOW 693 µs · repeats continuously

Illustrative playback; each displayed cycle is 1 second. HIGH/LOW proportions follow your inputs.

NE555 circuit & pin connections

555 astable circuit: all eight pinsR1 + R2 charge C; R2 discharges C through pin 7. Pins 2 and 6 share the capacitor node. Pins 8 and 4 connect to VCC. Pin 1 is grounded. Pin 5 connects to ground through a 10 nF capacitor. All ground symbols share the supply return.VCCR1R2C84VCCRESET7DISCH6THRES2TRIG555OUT3VoutCTRL510 nFGND1
R1 + R2 charge C; R2 discharges C through pin 7. Pins 2 and 6 share the capacitor node.
Wiring notes & pin reference

8 (VCC) and 4 (RESET) → supply positive. 1 (GND) → supply negative. 3 (OUT) → output. 5 (CTRL) → 10 nF → ground. Add 100 nF supply decoupling close to pins 8 and 1. All ground symbols connect to the same return.

VCC → R1 → pin 7 (DISCH) → R2 → pins 6 (THRES) and 2 (TRIG) → C → ground.

Logical schematic, not physical package layout. TI LM555 datasheet, figures 11 and 14.

Frequency687 Hz
Duty cycle52.4%
High time762 µs
Low time693 µs

Understand the result

What's going on

In astable mode, a 555 timer never settles - it charges a capacitor up, discharges it back down, and repeats forever, producing a square wave with no input signal needed at all. Two resistors and a capacitor set the pace.

The formula

t_high = 0.693 × (R1 + R2) × C

t_low = 0.693 × R2 × C

f = 1 / (t_high + t_low)

Show the derivation, mnemonic, and worked example

Build it up

The capacitor charges through both R1 and R2 together, which sets how long the output stays high. It then discharges through R2 alone, which sets how long the output stays low. Because charging always uses more resistance than discharging, the high time is always longer than the low time - a plain 555 astable can never produce a perfect 50/50 square wave.

Worked example

Worked example

R1 = 1 kΩ, R2 = 10 kΩ, C = 100 nF

t_high = 0.693 × 11,000 × 1e-7 ≈ 0.76 ms

t_low = 0.693 × 10,000 × 1e-7 ≈ 0.69 ms

f = 1 / (0.76 ms + 0.69 ms) ≈ 690 Hz