Try it

One trigger. One pulse.

Press Trigger. The output goes HIGH, then returns LOW and waits.

HIGHLOWTime
LOW: waiting for trigger

Calculated pulse: 1.1 s

Illustrative playback: 1.5 seconds on screen. Use the calculated pulse duration for the circuit.

NE555 circuit & pin connections

555 monostable circuit: all eight pinsR charges C at pins 6 and 7. A separate low pulse at pin 2 starts the one-shot timer. Pins 8 and 4 connect to VCC. Pin 1 is grounded. Pin 5 connects to ground through a 10 nF capacitor. All ground symbols share the supply return.VCCRTrigger inputActive lowC84VCCRESET7DISCH6THRES2TRIG555OUT3VoutCTRL510 nFGND1
R charges C at pins 6 and 7. A separate low pulse at pin 2 starts the one-shot timer.
Wiring notes & pin reference

8 (VCC) and 4 (RESET) → supply positive. 1 (GND) → supply negative. 3 (OUT) → output. 5 (CTRL) → 10 nF → ground. Add 100 nF supply decoupling close to pins 8 and 1. All ground symbols connect to the same return.

VCC → R → pins 7 (DISCH) and 6 (THRES) → C → ground. Drive pin 2 (TRIG) from a normally-high external signal; pulse below VCC/3, then return high before the timer expires. Do not leave this input floating.

Logical schematic, not physical package layout. TI LM555 datasheet, figures 11 and 14.

Pulse width1.1 s

Understand the result

What's going on

In monostable mode, a 555 timer sits quietly until it’s triggered - then it outputs one clean pulse of a fixed length and goes back to waiting. It’s the “one-shot” mode: a short low trigger pulse starts one timed action. Return the trigger high before the timing interval ends; holding it low can extend the output pulse.

The formula

T = 1.1 × R × C

T is the pulse width in seconds, R in ohms, C in farads.

Show the derivation, mnemonic, and worked example

Build it up

The trigger starts a single charge cycle on the capacitor through the resistor. The output stays high for as long as that charge takes to cross a fixed internal threshold - about two-thirds of the supply voltage. Bigger R or bigger C means the capacitor takes longer to reach that threshold, so the pulse lasts longer.

Worked example

Worked example

R = 100 kΩ, C = 10 µF

T = 1.1 × 100,000 × 0.00001

T = 1.1 seconds